Is there a method to calculate........
01-20-2016, 08:17 PM
#12
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Originally Posted by zozee
If one quilter boarded a train from New York to Chicago at 3:45 pm with 27 yards of fabric And a long arm, , and another quilter boarded a train from Omaha to Chicago at 2:30 pm with 13 yards and a Featherweight, how much chocolate would they eat in Paducah?
01-20-2016, 08:19 PM
#13
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Originally Posted by zozee
If one quilter boarded a train from New York to Chicago at 3:45 pm with 27 yards of fabric And a long arm, , and another quilter boarded a train from Omaha to Chicago at 2:30 pm with 13 yards and a Featherweight, how much chocolate would they eat in Paducah?
Cari
01-20-2016, 09:10 PM
#14
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Originally Posted by zozee
If one quilter boarded a train from New York to Chicago at 3:45 pm with 27 yards of fabric And a long arm, , and another quilter boarded a train from Omaha to Chicago at 2:30 pm with 13 yards and a Featherweight, how much chocolate would they eat in Paducah?
01-20-2016, 09:13 PM
#15
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Edit: Correct numbers are in bold.
Originally Posted by Bree123
Are you counting each direction change? If so, you would have 312 possible combinations. If not, it's 78.
You need to add each consecutive number together to get the total. If you have 4 different layouts, then you need to also multiply the answer by 4.
12+11+10+9+8+7+6+5+4+3+2+1=78 | 75x4=312
Note: The above answer includes matching together 2 of the same fabrics (will look like a square of that fabric). If you don't want that option, get rid of the highest number.
11+10+9+8+7+6+5+4+3+2+1=66 | 66x4=264
[ATTACH=CONFIG]540704[/ATTACH]
You need to add each consecutive number together to get the total. If you have 4 different layouts, then you need to also multiply the answer by 4.
12+11+10+9+8+7+6+5+4+3+2+1=78 | 75x4=312
Note: The above answer includes matching together 2 of the same fabrics (will look like a square of that fabric). If you don't want that option, get rid of the highest number.
11+10+9+8+7+6+5+4+3+2+1=66 | 66x4=264
[ATTACH=CONFIG]540704[/ATTACH]
01-21-2016, 03:31 AM
#16
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Originally Posted by zozee
If one quilter boarded a train from New York to Chicago at 3:45 pm with 27 yards of fabric And a long arm, , and another quilter boarded a train from Omaha to Chicago at 2:30 pm with 13 yards and a Featherweight, how much chocolate would they eat in Paducah?
In response to the OP, this is a fab book and not too expensive.
[ATTACH=CONFIG]540726[/ATTACH]
01-21-2016, 03:45 AM
#17
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LOL!!!!! @ zozee! That's about how much sense maths makes for me. Thank you everyone for your input 
I followed up on ghostrider's comment and found an online calculator for calculating the combinations
http://www.mathsisfun.com/combinator...alculator.html
Once again the Quilting Board members have solved my problem and made my quilting life a whole lot easier! Such stars!!!
Thank you!
I followed up on ghostrider's comment and found an online calculator for calculating the combinationshttp://www.mathsisfun.com/combinator...alculator.html
Once again the Quilting Board members have solved my problem and made my quilting life a whole lot easier! Such stars!!!
Thank you!
01-21-2016, 04:53 AM
#19
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Location: Florida
Posts: 1,135
Originally Posted by ghostrider
It's called permutations and combinations in the math world. Permutations are where order matters, combinations are where it doesn't.
http://betterexplained.com/articles/...-combinations/
In your HST example, order doesn't matter, so it's a combination. And specifically how many combinations of r objects (2 in this case) from a set of n objects (12 in this case). Without getting into too much detail or terminology, the answer is 66.
12 · 11 ÷ 2 · 1 = 132 ÷ 2 = 66
Another example: if you wanted to know the number of different four patches you could make with 20 fabrics, it would be:
20 · 19 · 18 · 17 ÷ 4 · 3 · 2 · 1 = 116,280 ÷ 24 = 4,845
Have fun!
http://betterexplained.com/articles/...-combinations/
In your HST example, order doesn't matter, so it's a combination. And specifically how many combinations of r objects (2 in this case) from a set of n objects (12 in this case). Without getting into too much detail or terminology, the answer is 66.
12 · 11 ÷ 2 · 1 = 132 ÷ 2 = 66
Another example: if you wanted to know the number of different four patches you could make with 20 fabrics, it would be:
20 · 19 · 18 · 17 ÷ 4 · 3 · 2 · 1 = 116,280 ÷ 24 = 4,845
Have fun!
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