5y + 13 = 2y - 2
Remember--get all the y's on one side--all the whole numbers on the other.
So, move the 2y to the other side, or subtract it from both sides so everything is even. Once it's taken away from both sides you get 3y+13=-2.
now get the whole numbers on one side by subtracting 13 from both sides. So then you have 3y=-15. Ask yourself what multiplied by 3 will give me -15 and it's -5.
The correct answer, marked on my test, is -5. I am trying to redo my wrong answers to learn how to do the steps right. I just don't know how to do it.
Here is another one I missed.
-2(x - 5) + 4 = 4(2x-4) The correct answer is 3, but I don't understand how to do it. Thanks in advance!![/quote]
-2(x-5) + 4 = 4(2x-4)
Here you go!
-2 times x=-2x, then do
-2 times -5=10
4 times 2x = 8x, then do
4 times 4 = 16
So, once you multiply all that out you get:
-2x + 10 + 4 = 8x-16
Remember you need to get the x alone, so, next add 2x to each side to cancel out the -2x
and you have 10 + 4 = 10x-16
Then, get the 16 out of there by adding 16 to each side--which cancels out the 16 on the right--and you get:
14+16=10x
Then 30=10x and what multiplied by 10 = 30? 3, so x=3.